Vector Addition

Introduction

What a Vector Represents in Simple Terms

Why Adding Vectors Matters

Geometric Addition: The Tip‑to‑Tail Method

Understanding Vector Components

Algebraic Addition Using Components

Common Mistakes and How to Avoid Them

Visual Intuition: How Direction and Length Combine

Practice Problems Worked Step‑by‑Step

Calculator

Addition

  • Addition (and subtraction) works the same as normal numbers:
add([1, 2], [3, 4]) [1, 2] + [3, 4] [1, 2] - [3, 4]

Exercises

Try these on your own. Draw diagrams where helpful.

  1. Add the vectors $\vec{a} = (1, 4)$ and $\vec{b} = (3, -2)$.

    Solution

    Add the vectors \(\vec{a} = (1, 4)\) and \(\vec{b} = (3, -2)\)

    • \(x\)-components: \(1 + 3 = 4\)
    • \(y\)-components: \(4 + (-2) = 2\)
    • Solution: \((4, 2)\)
  2. Two vectors of lengths 6 and 8 point in the same direction. What is their sum’s length?

    Solution

    Two vectors of lengths 6 and 8 point in the same direction. What is the sum’s length?

    • Same direction → lengths simply add.
    • Solution: \(6 + 8 = 14\)
  3. Two vectors of lengths 5 and 7 point in opposite directions. What is the length of the sum?

    Solution

    Two vectors of lengths 5 and 7 point in opposite directions. What is the length of the sum?

    • Opposite directions → subtract lengths.
    • Solution: \(|7 - 5| = 2\)
  4. Add the vectors $\vec{u} = (-2, 3)$ and $\vec{v} = (4, 1)$.

    Solution

    Add the vectors \(\vec{u} = (-2, 3)\) and \(\vec{v} = (4, 1)\)

    • \(x\)-components: \(-2 + 4 = 2\)
    • \(y\)-components: \(3 + 1 = 4\)
    • Solution: \((2, 4)\)
  5. A vector of length 10 makes a $30^\circ$ angle with the horizontal. Find its components.

    Solution

    A vector of length 10 makes a \(30^\circ\) angle with the horizontal. Find its components.

    • Horizontal: \(10\cos 30^\circ = 10 \cdot \frac{\sqrt{3}}{2} = 5\sqrt{3}\)
    • Vertical: \(10\sin 30^\circ = 10 \cdot \frac{1}{2} = 5\)
    • Solution: \((5\sqrt{3},\, 5)\)
  6. Draw two perpendicular vectors of lengths 3 and 4. Use geometry to find the resultant.

    Solution

    Draw two perpendicular vectors of lengths 3 and 4. Use geometry to find the resultant.

    • Right triangle with legs 3 and 4.
    • Resultant length:
      \[
      \sqrt{3^2 + 4^2} = 5
      \]
    • Solution: Resultant length is 5.
  7. Add $\vec{p} = (0, 5)$ and $\vec{q} = (-3, -1)$.

    Solution

    Add \(\vec{p} = (0, 5)\) and \(\vec{q} = (-3, -1)\)

    • \(x\)-components: \(0 + (-3) = -3\)
    • \(y\)-components: \(5 + (-1) = 4\)
    • Solution: \((-3, 4)\)
  8. A person walks 4 km east, then 2 km north. Draw and label the resultant vector.

    Solution

    A person walks 4 km east, then 2 km north. Draw and label the resultant vector.

    • Components: \((4, 2)\)
    • Length:
      \[
      \sqrt{4^2 + 2^2} = \sqrt{20} = 2\sqrt{5}
      \]
    • Solution: Resultant vector is \((4, 2)\) with length \(2\sqrt{5}\).
  9. Add the vectors $\vec{a} = (7, -3)$ and $\vec{b} = (-2, 5)$.

    Solution

    Add the vectors \(\vec{a} = (7, -3)\) and \(\vec{b} = (-2, 5)\)

    • \(x\)-components: \(7 + (-2) = 5\)
    • \(y\)-components: \(-3 + 5 = 2\)
    • Solution: \((5, 2)\)
  10. Two vectors form a $60^\circ$ angle and have lengths 5 and 5. estimate the resultant length.

    Solution

    Two vectors form a \(60^\circ\) angle and have lengths 5 and 5. Estimate the resultant length.

    Using the law of cosines:
    \[
    R = \sqrt{5^2 + 5^2 + 2\cdot 5\cdot 5\cos 60^\circ}
    \]
    \[
    R = \sqrt{25 + 25 + 50 \cdot \tfrac{1}{2}} = \sqrt{25 + 25 + 25} = \sqrt{75}
    \]
    \[
    R = 5\sqrt{3} \approx 8.66
    \]

    • Solution: Approximately 8.66.