Vector AdditionIntroductionVectors are quantities with both direction and length.Adding vectors tells us the combined effect of two or more movements, forces, or changes.This article shows two friendly ways to add vectors: Geometrically (drawing pictures)Algebraically (using numbers)What a Vector Represents in Simple TermsA vector can represent:A movement (e.g., “walk 3 steps east”)A force (e.g., “push 5 N upward”)A velocity (e.g., “10 m/s north”)Think of a vector as an arrow: Length = how big the quantity isDirection = which way it pointsWhy Adding Vectors MattersMany real‑world situations involve combining effects:Two forces acting on an objectTwo movements happening one after anotherWind + airplane velocityVector addition gives the overall result.Geometric Addition: The Tip‑to‑Tail MethodThis is the most visual way to add vectors.Steps:Draw the first vector as an arrow.Place the tail of the second vector at the tip of the first.Draw the resultant vector from the tail of the first to the tip of the second.The final arrow is the sum: $$\vec{a} + \vec{b} = \vec{r}$$Understanding Vector ComponentsAny vector in a plane can be broken into horizontal and vertical parts:If a vector has length $L$ and angle $\theta$:Horizontal component: $L\cos\theta$Vertical component: $L\sin\theta$Components let us work with vectors using simple arithmetic.Algebraic Addition Using ComponentsIf $$\vec{a} = (a_x, a_y), \quad \vec{b} = (b_x, b_y),$$ then $$\vec{a} + \vec{b} = (a_x + b_x,\; a_y + b_y).$$Steps:Add the $x$‑components.Add the $y$‑components.The result is the new vector.Common Mistakes and How to Avoid ThemMistake: Adding lengths but ignoring direction. Fix: Always consider direction; vectors are not just numbers.Mistake: Drawing arrows without consistent scale. Fix: Use the same scale for all vectors in a diagram.Mistake: Mixing up components. Fix: Keep $x$ and $y$ components separate and labelled.Visual Intuition: How Direction and Length CombineAdding vectors is like combining movements:Move along $\vec{a}$, then along $\vec{b}$ → total movement is $\vec{a} + \vec{b}$.If vectors point in similar directions:The sum is longer.If they point in opposite directions:The sum is shorter or may even reverse direction.If they are perpendicular:The sum forms the hypotenuse of a right triangle.Practice Problems Worked Step‑by‑StepExample 1: $\vec{a} = (3, 1)$ and $\vec{b} = (2, 4)$Add components:$x$: $3 + 2 = 5$$y$: $1 + 4 = 5$Result: $\vec{a} + \vec{b} = (5, 5)$Example 2: Two vectors of lengths 4 and 3 at right angles.Resultant length: $$\sqrt{4^2 + 3^2} = 5.$$CalculatorAdditionAddition (and subtraction) works the same as normal numbers:add([1, 2], [3, 4]) [1, 2] + [3, 4] [1, 2] - [3, 4]ExercisesTry these on your own. Draw diagrams where helpful.Add the vectors $\vec{a} = (1, 4)$ and $\vec{b} = (3, -2)$.SolutionAdd the vectors \(\vec{a} = (1, 4)\) and \(\vec{b} = (3, -2)\)\(x\)-components: \(1 + 3 = 4\)\(y\)-components: \(4 + (-2) = 2\)Solution: \((4, 2)\)Two vectors of lengths 6 and 8 point in the same direction. What is their sum’s length?SolutionTwo vectors of lengths 6 and 8 point in the same direction. What is the sum’s length?Same direction → lengths simply add.Solution: \(6 + 8 = 14\)Two vectors of lengths 5 and 7 point in opposite directions. What is the length of the sum?SolutionTwo vectors of lengths 5 and 7 point in opposite directions. What is the length of the sum?Opposite directions → subtract lengths.Solution: \(|7 - 5| = 2\)Add the vectors $\vec{u} = (-2, 3)$ and $\vec{v} = (4, 1)$.SolutionAdd the vectors \(\vec{u} = (-2, 3)\) and \(\vec{v} = (4, 1)\)\(x\)-components: \(-2 + 4 = 2\)\(y\)-components: \(3 + 1 = 4\)Solution: \((2, 4)\)A vector of length 10 makes a $30^\circ$ angle with the horizontal. Find its components.SolutionA vector of length 10 makes a \(30^\circ\) angle with the horizontal. Find its components.Horizontal: \(10\cos 30^\circ = 10 \cdot \frac{\sqrt{3}}{2} = 5\sqrt{3}\)Vertical: \(10\sin 30^\circ = 10 \cdot \frac{1}{2} = 5\)Solution: \((5\sqrt{3},\, 5)\)Draw two perpendicular vectors of lengths 3 and 4. Use geometry to find the resultant.SolutionDraw two perpendicular vectors of lengths 3 and 4. Use geometry to find the resultant.Right triangle with legs 3 and 4.Resultant length: \[ \sqrt{3^2 + 4^2} = 5 \]Solution: Resultant length is 5.Add $\vec{p} = (0, 5)$ and $\vec{q} = (-3, -1)$.SolutionAdd \(\vec{p} = (0, 5)\) and \(\vec{q} = (-3, -1)\)\(x\)-components: \(0 + (-3) = -3\)\(y\)-components: \(5 + (-1) = 4\)Solution: \((-3, 4)\)A person walks 4 km east, then 2 km north. Draw and label the resultant vector.SolutionA person walks 4 km east, then 2 km north. Draw and label the resultant vector.Components: \((4, 2)\)Length: \[ \sqrt{4^2 + 2^2} = \sqrt{20} = 2\sqrt{5} \]Solution: Resultant vector is \((4, 2)\) with length \(2\sqrt{5}\).Add the vectors $\vec{a} = (7, -3)$ and $\vec{b} = (-2, 5)$.SolutionAdd the vectors \(\vec{a} = (7, -3)\) and \(\vec{b} = (-2, 5)\)\(x\)-components: \(7 + (-2) = 5\)\(y\)-components: \(-3 + 5 = 2\)Solution: \((5, 2)\)Two vectors form a $60^\circ$ angle and have lengths 5 and 5. estimate the resultant length.SolutionTwo vectors form a \(60^\circ\) angle and have lengths 5 and 5. Estimate the resultant length.Using the law of cosines: \[ R = \sqrt{5^2 + 5^2 + 2\cdot 5\cdot 5\cos 60^\circ} \] \[ R = \sqrt{25 + 25 + 50 \cdot \tfrac{1}{2}} = \sqrt{25 + 25 + 25} = \sqrt{75} \] \[ R = 5\sqrt{3} \approx 8.66 \]Solution: Approximately 8.66.